WebJan 20, 2024 · 6. For Christoffel symbol and metric, we've the following identity. 1 2 g α γ ( g α β, μ + g α μ, β − g β μ, α) = Γ γ β μ. Now even though I've seen the derivation, I still can't understand what is the motivation behind the steps taken, in all the index juggling being done. Can anyone please give a motivated proof for the identity? WebFeb 21, 2024 · From their indices, the Christoffel symbols look like components of a ( 1, 2) -tensor, so assuming that the connection is such a tensor makes sense to me. However, …
Christoffel symbols - HandWiki
WebSep 9, 2016 · I have a problem with derivation of the transformation law for Christoffel symbols: two different approaches give me two different results. I assume that the equation for the covariant derivative of a vector shall be transformed as a tensor and transform it and those parts in it which I know. WebUsing the metric above, we find the Christoffel symbols, where the indices are . The sign denotes a total derivative of a function. Using the field equations to find A(r) and B(r) [ edit] To determine and , the vacuum field equations are employed: Hence: where a comma is used to set off the index that is being used for the derivative. inyectores eui
Deriving the transformation law for the Christoffel symbols
WebCHRISTOFFEL SYMBOLS AND THE COVARIANT DERIVATIVE 2 where g ij is the metric tensor. Keep in mind that, for a general coordinate system, these basis vectors need not … WebPhysically, Christoffel symbols can be interpreted as describing fictitious forces arising from a non-inertial reference frame. In general relativity, Christoffel symbols represent … WebThese Christoffel symbols are defined in terms of the metric tensor of a given space and its derivatives: Here, the index m is also a summation index, since it gets repeated on each term (a good way to see which indices are being summed over is to see whether an index appears on both sides of the equation; if it doesn’t, it’s a summation index). on ring